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11x^2=-9x-1
We move all terms to the left:
11x^2-(-9x-1)=0
We get rid of parentheses
11x^2+9x+1=0
a = 11; b = 9; c = +1;
Δ = b2-4ac
Δ = 92-4·11·1
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{37}}{2*11}=\frac{-9-\sqrt{37}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{37}}{2*11}=\frac{-9+\sqrt{37}}{22} $
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